a) N2(g) + 4H2(g) + Cl2(g) + 4O2(g) --> 2 NH4ClO4(s), b) N(g) + 2H2(g) + Cl2(l) + 2O2(g) --> NH4ClO4(s), c) 1/2 N2(g) + 2H2(g) + 1/2 Cl2(g) + 2O2(g) --> NH4ClO4(s), d) N(g) + 4H(g) + Cl(g) +4O(g) --> NH4ClO4(s), e)N(g) + 2H2(g) + Cl(g) + 2O2(g) --> NH4ClO4(s). answer! Question: Calculate The Standard Molar Enthalpy Of Formation Of FeCl2(s) Using The Following Standard Enthalpy Of Reaction Values. N2(g) + 4H2(g) + Cl2(g) + 4O2(g) --> 2NH4ClO4(s). Looking at the reaction... Our experts can answer your tough homework and study questions. The standard enthalpy of formation (ΔH 0 f) of a compound is the change in enthalpy that accompanies the formation of 1 mole of a compound from its elements with all substances in their standard states. Start off by balancing the equation: 2Na(s) + F2(s) ---> chemistry. These are molar heats of formation for anions and cations in aqueous solution. We would routinely balance the equation like this, but that forms two moles of NH4ClO4. answered • 06/11/18, Ph.D. University Professor with 10+ years Tutoring Experience. The standard enthalpy of formation of HCl(g) is - 92.3 kJ/mol. The standard enthalpy of formation (ΔH 0 f) of a compound is the change in enthalpy that accompanies the formation of 1 mole of a compound from its elements with all substances in their standard states. Elements in their standard state are said to have a standard enthalpy of formation of zero as a reference. Divide all the coefficients by 2 to make one mole of NH4ClO4. No packages or subscriptions, pay only for the time you need. ? removes tool for defrauded students, Chappelle's Netflix show removed at his request, Publix worker's family blames policy for COVID-19 death, Experts warn of COVID-19 'surge' after Thanksgiving, Cowboys strength coach suffers medical emergency, OxyContin maker pleads guilty to federal charges, Director apologizes for snarky comments made over Zoom. The standard enthalpy of formation is defined as the heat change when one mole of a substance is formed from its standard state elements at a pressure of 1 atm. The standard enthalpy of formation is the change in enthalpy that accompanies the formation of one mole of the compound from its elements. The heat of formation is the enthalpy change associated with making one mole of the compound from the elements in their standard states. 3) The species which by definition has zero standard molar enthalpy of formation at 298 K is: (IIT JEE - 2010) a) CH 4 (g) b) Br 2 (g) c) Cl 2 (g) d) H 2 O(g) Explanation: As mentioned in above problem, the standard molar enthalpy of formation of element in its standard state is taken as zero. Most questions answered within 4 hours. These tables include heat of formation data gathered from a variety of sources, including the primary and secondary literature, as well as the NIST Chemistry WebBook. Do the dipoles cancel in this molecule? J.R. S. Dasent, "Inorganic Energetics," 2nd ed., Cambridge University Press, NY, … Acetic acid has an empirical formula of CH2O and molar mass of 60 g/mol. For the reaction of {eq}H_2(g)\:+\:Cl_2(g)\:\rightarrow \:2HCl(g) A scientist measures the standard enthalpy change for the following reaction to be -25.6 kJ : I2(g) + Cl2(g)2ICl(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of ICl(g) is_____kJ/mol 1, 2] enthalpy of formation based on version 1.118 of the Thermochemical Network This version of ATcT results was partially described in Ruscic et al. Standard Enthalpy of Formation* for Atomic and Molecular Ions Cations ΔH˚ f (kJ/mol) Cations ΔH˚ f (kJ/mol) Anions ΔH˚ f (kJ/mol) Anions ΔH˚ f (kJ/mol) Ag+(aq) +105.9 K+(aq) −251.2 Br−(aq) −120.9 H 2PO 4 −(aq) −1302.5 Al3+(aq) −524.7 Li+(aq) −278.5 Cl−(aq) −167.4 HPO 4 2−(aq) −1298.7 Ba2+(aq) −538.4 Mg2+(aq) −462.0 ClO

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